Two masses M1=4.60 kg and M2=5.90 kg are stacked on top of each other as shown i

Question

Two masses M1=4.60 kg and M2=5.90 kg are stacked on top of each other as shown in the figure. The static coefficient of friction between M1 and M2 is ?s=0.190. There is no friction between M2 and the surface below it. What is the maximum horizontal force that can be applied to M1 without M1 sliding relative to M2? (in N)

Two masses M1=4.60 kg and M2=5.90 kg are stacked on top of each other as shown in the figure. The static coefficient of friction between M1 and M2 is ?s=0.190. There is no friction between M2 and the surface below it. What is the maximum horizontal force that can be applied to M1 without M1 sliding relative to M2? (in N)

Explanation / Answer

F = s * M1*g.

= 0.31* (3.4 x 9.8)

=10.329N

==========================================

a = F/m = 10.329 / 3.40 = 3.038m /s^2

m = M1 + M2 = 3.4+8.9 = 12.3 kg

F = ma = 12.3*3.038 = 37.367N

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