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A thin rectangular plate of uniform areal density ? = 2.89 kg/m 2 has length of

ID: 2242084 • Letter: A

Question

A thin rectangular plate of uniform areal density ? = 2.89 kg/m2 has length of 38.0 cm and width of 27.0 cm. The lower left hand corner is located at the origin, (x,y)= (0,0) and the length is along the x-axis.

(a) There is a circular hole of radius 8.00 cm with center at (x,y) = (13.00,11.50) cm in the plate. Calculate the mass of plate.

(b) Calculate the x-coordinate of CM of the plate.

(c) Calculate the distance of the plate's CM from the origin.


A thin rectangular plate of uniform areal density ? = 2.89 kg/m2 has length of 38.0 cm and width of 27.0 cm. The lower left hand corner is located at the origin, (x,y)= (0,0) and the length is along the x-axis. There is a circular hole of radius 8.00 cm with center at (x,y) = (13.00,11.50) cm in the plate. Calculate the mass of plate. Calculate the x-coordinate of CM of the plate. Calculate the distance of the plate's CM from the origin.

Explanation / Answer



a)
the total mass, M = density*area

M = 2.89*0.38*0.27

M = 0.297 kg

let m bethe mass of the circular plate, m = density*area


= 2.89*pi*0.08^2

= 0.058 kg

m' is the mass of remaining part

m' = M- m = 0.297 - 0.058 = 0.239 kg


b)


x1,y1 represents center of mass of the circular plate

x1 = 13 cm
y1 = 11.5 cm



x2 , y2 is the x coordinate of center of mass of remaining plate.


Xcm is x coordinate of center of mass of system

.Xcm = 19.......Ycm = 13.5 cm

Xcm = m*x1+m'*x2/(m+m')

19 = ((0.058*13)+(0.239*x2))/0.297

x2 = 20.456 cm

Ycm = m*y1+m'*y2/(m+m')

13.5 = ((0.058*11.5)+(0.239*y2))/0.297

y2 = 13.985 cm

c) r2 = sqrt(x2^2+y2^2) = sqrt(20.456^2+13.985^2)

r2 = 24.78 cm

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