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A thin layer of transparent oil is placed on top of a glassplate. The oil film i

ID: 1677429 • Letter: A

Question

A thin layer of transparent oil is placed on top of a glassplate. The oil film is illuminated by shining a narrow bearof white light perpendicularly onto oil's surface. Index ofrefraction of air = 1.0, index of refraction for oil = 1.4 andindex of refraction for glass = 1.5 The film appears green. This corresponds to a wavelengthof 520 nm Determine each of the following for the green light: a) frequency of the light in air b) frequency of light in oil film c) wavelength of light in oil film d) Calculate minimum thickness of oil film (other than zero)such that observed green light is most intense e) As angle of light source changes, light you observe fromfilm changes color. Explain A thin layer of transparent oil is placed on top of a glassplate. The oil film is illuminated by shining a narrow bearof white light perpendicularly onto oil's surface. Index ofrefraction of air = 1.0, index of refraction for oil = 1.4 andindex of refraction for glass = 1.5 The film appears green. This corresponds to a wavelengthof 520 nm Determine each of the following for the green light: a) frequency of the light in air b) frequency of light in oil film c) wavelength of light in oil film d) Calculate minimum thickness of oil film (other than zero)such that observed green light is most intense e) As angle of light source changes, light you observe fromfilm changes color. Explain

Explanation / Answer

nair=1.0 noil=1.4 nglass=1.5 green=520 nm A.) f=c/ f=3.00x108m/s/520x10-9m f=5.76x1014Hz Do C first. C.) oil=/noil oil=520x10-9m/1.4 oil=371.4 nm B.) f=c/oil f=3x108m/s/371.4x10-9m f=8.07x1014Hz D.) Thickness equation: 2t= m/n where m is the order numberm=1 2t=1.00(520x10-9m)/1.4 t=185.47nm E.) This happens because the light may become a prism which thecolors appear at different angles. Please email me if you have questions.

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