A patient with CP is reaching for an object. You are given the following positio

Question

A patient with CP is reaching for an object. You are given the following positions [in cm]:- initial hand position = 10, 10- mid point hand position = 70, 90- final position hand position = 130, 90What is the Index of Curvature (Displacement/Distance Ratio) for this movement? During a golf drive, the angular velocity of the driver is 1150 deg/s just before impact with the golf ball. If the distance from the club head to the axis of rotation is 2.0 m, what is the linear velocity of the club head?

Explanation / Answer

PArt 1

total displacement = sqrt[(130-10)^2 + (90-10)^2] = 144.22

total distance covered = sqrt[(70-10)^2 + (90-10)^2] + sqrt[(130-70)^2 + 0] = 100 + 60 = 160

index of curvature = 144.22/160 = .901

Part 2

angluar velocity = 1150 degree/sec = 1150*3.14/180 = 20.07 rad/sec

linear velocity = angular velocity*R

= 20.07*2 = 40.14 m/sec

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.