The two wires shown in the figure carry currents of I = 5.39 A in opposite direc
ID: 2238901 • Letter: T
Question
The two wires shown in the figure carry currents of I = 5.39 A in opposite directions and are separated by a distance of d0 = 8.93 cm. Calculate the net magnetic field at a point midway between the wires. Use the direction out of the page as the positive direction and into the page as the negative direction in your answer. Tries 0/12 Calculate the net magnetic field at point P1 - that is 9.97 cm to the right of the wire on the right. Tries 0/12 Calculate the net magnetic field at point P2 - that is 18.9 cm to the left of the wire on the left.Explanation / Answer
B = 2*(?o*I/2?r) = (but ?o/2? = 2.0X10^-7)
so B = 2*(2.0x10^-7*5.39/(0.0893/2)
= 4.82x10^-5T (IN)
b) Here the left wire creates a field into the page and the right wire is out
so the net field will be IN
B = ?o/2?*(I1/0.0893 - I2/(0.0997 + 0.0893))
= 2.0x10^-7*(5.39/0.0967 - 5.39/(0.0933 + 0.0967) =
= 5.474x10^-6 T IN
c) Now the net field will be OUT
B = ?o/2?*(I1/0.189 - I2/(0.0893 + 0.189))
= 2.0x10^-7*(5.39/0.189 - 5.39/(0.0893 + 0.189) =
= 1.831x10^-6 T OUT
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