The two wires shown in the figure below are separated by d = 10.5 cm and carry c

Question

The two wires shown in the figure below are separated by d = 10.5 cm and carry currents of I = 4.85 A in opposite directions.

(a) Find the magnitude and direction of the net magnetic field at a point midway between the wires.

(b) Find the magnitude and direction of the net magnetic field at point P1, 10.5 cm to the right of the wire on the right.

(c) Find the magnitude and direction of the net magnetic field at point P2, 2d = 21.0 cm to the left of the wire on the left.

Explanation / Answer

part 1) So B = 2*(o*I/2r) = (but o/2 = 2.0X10^-7)

so B = 2*(2.0x10^-7*4.85/(0.105/2) = 3.69x10^-5T (INWARDS) = 3.69 uT

PART 2) B = o/2*(I1/0.105 - I2/(0.105 + 0.105)) = 2.0x10^-7*(4.85/0.105 - 4.85/(0.105 + 0.105) =

= 4.61x10^-6 T (INWARDS) = 4.61 uT

PART 3)

B = o/2*(I1/0.21 - I2/(0.105 + 0.21)) = 2.0x10^-7*(4.85/0.21 - 4.85/(0.105 + 0.21) =

= 1.5396 x10^-6 T (OUTWARDS) = 1.5396 uT

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