The two spheres in the figure below surround equal charges. Three students are d
ID: 1426534 • Letter: T
Question
The two spheres in the figure below surround equal charges. Three students are discussing the situation. Student Is The fluxes through spheres A and B are equal because they enclose equal charges. Student 2 s But the electric field on sphere B is weaker than the electric field on sphere A. The flux depends on the electric field strength, so Student 3 s I thought we learned that flux was about surface area. Sphere B is larger than sphere A, so I think the flux through B is larger than the flux through A. Which of these students, if any, do you agree with? A particle with a charge +Q is inside a spherical Gaussian surface, and three other charges (one with a charge +Q and two with a charge -Q) are outside the Gaussian surface, as shown below. The net electric flux through the surface is -g (a) greater than zero (flowing out of the sphere). equal to zero. less than zero (flowing into the sphere). Two concentric imaginary spherical surfaces of radius R and 2R respectively surround a positive point charge Q located at the center of the surfaces. When compared to the electric flux through the surface of radius R the electric flux theta_2 through the surface of radius 2R is the flux through A is larger than the flux through B.Explanation / Answer
12) Flux = total charge enclosed/epsilon
As here total charge is same for both so flux through the spheres would be same
if E is weak for larger sphere then its area is large so E.A again give same quantity for flux
13) Net flux depends the charge enclosed by the surface
and here +Q charge is enclosed here so flux will be positive and greataer than zero (flowing out ot the sphere)
14) As the charge enclosed bu both surface is same so flux passing through both surface will also be same
option c is correct Phi2 = phi1
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