The two wires shown in the figure carry currents of I = 5.48 A in opposite direc

Question

The two wires shown in the figure carry currents of I = 5.48 A in opposite directions and are separated by a distance of do = 9.38 cm. Calculate the net magnetic field at a point midway between the wires. Use the direction out of the page as the positive direction and into the page as the negative direction in your answer. Submit Answer Tries 0/99 Calculate the net magnetic field at point P1 that is 8.02 cm to the right of the wire on the right. Sutomt Anewor Tries o/99 Calculate the net magnetic field at point P2 that is 18.5 cm to the left of the wire on the left. Tries 0/99 Submit Answer

Explanation / Answer

At a point midway between the wires

B = B1+B2 = (mu_o*I1)/(2*pi*r) + (mu_o*I2/(2*pi*r2)

B1 = ((4*3.142*10^-7*5.48)/(2*3.142*(0.0938/2))) = 2.34*10^-5 T

B2 = mu_o*I2/(2*pi*r) = ((4*3.142*10^-7*5.48)/(2*3.142*(0.0938/2))) = 2.34*10^-5 T

B = 2*2.34*10^-5 = 4.68*10^-5 T into the page

at point P1

B1 = (mu_o*I1)/(2*pi*r1) = ((4*3.142*10^-7*5.48)/(2*3.142*(0.0938+0.0802))) = 6.29*10^-6 T into the page

B2 = (mu_o*I2)/(2*pi*r2) = (4*3.142*10^-7*5.48)/(2*3.142*0.0802)) = 13.6*10^-6 T out of the page

B = -B1+B2 = (-6.29+13.6)*10^-6 = 7.31*10^-6 T out of the page

at point P2

B1 = (mu_o*I1)/(2*pi*r1) = ((4*3.142*10^-7*5.48)/(2*3.142*0.185)) = 5.92*10^-6 out of the page

B2 = (mu_o*I2)/(2*pi*r2) = ((4*3.142*10^-7*5.48)/(2*3.142*(0.185+0.0938))) = 3.93*10^-6 into the page

B = B1+B2 = (5.92-3.93)*10^-6 = 1.99*10^-6 T out of the page

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