Two long, parallel wires carry currents of I1 = 2.76 A and I2 = 5.50 A in the di

Question

Two long, parallel wires carry currents of I1 = 2.76 A and I2 = 5.50 A in the direction indicated in the figure below. (Choose the line running from wire 1 to wire 2 as the positive x-direction and the line running upward as the positive y direction.) Find the magnitude and direction of the magnetic field at a point midway between the wires (d = 20.0 cm). magnitude Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. mu T direction The response you submitted has the wrong sign. degree (counterclockwise from the +x-axis) Find the magnitude and direction of the magnetic field at point P, located d = 20.0 cm above the wire carrying the 5.50-A current. Magnitude Your response differs from the correct answer by more than 10%. Double check your calculations. mu T directions Your response differs from the correct answer by more than 10%. Double check your calculations. degree (counterclockwise from the +x-axis)

Explanation / Answer

a)B=muo*i1/2*pi*(d/2) -muo*i2/2*pi*(d/2)=muo*(i1-i2)/pi*d=-5.48*10^-6 T ,direction is negative y, b)B=muo*i2/2*pi*d (-i)+muo*i1/2*pi*sqrt(2)*d *[cos(45) j-sin(45) i] Bx=-muo*i2/2*pi*d-muo*i1*sin(45)/2*sqrt(2)*pi*d=-6.88*10^-6 T By=muo*i1*cos(45)/2*sqrt(2)*pi*d=1.38*10^-6 T B=sqrt[Bx^2+By^2]=7.01*10^-6 T theta=tan inverse(By/Bx)=11.34 degree north of west=168.65 degree counter clockwise from positive x axis

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.