A golf ball is struck at ground level. The speed of the golf ball as a function

Question

A golf ball is struck at ground level. The speed of the golf ball as a function of time is shown in the figure below, where t = 0 at the instant the ball is struck. The graph is marked in increments of 0.25 s along the time axis, and vmin = 15.50 m/s and vmax = 19.76 m/s. (Values in figure do not necessarily match values in problem).

(a) How far does the golf ball travel horizontally before returning to ground level? ..... m ?

(b) What is the maximum height above the ground level attained by the ball? ..... m ?

show steps please!

Explanation / Answer

1) since this is an example of projectile motion, Vmin would be the horizontal component of velocity .

so the time of flight=2.5 s

so the distance covered=Vx*t

=38.75 m

2)the horizontal component of the velocity will be (19.76^2-15.5^2)^1/2

=12.256 m/s

so the maximum height reached=vy^2/2g

=7.6636 m

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