A golf analyst claims that the standard deviation of the 18-hole scores for a go
ID: 3324312 • Letter: A
Question
A golf analyst claims that the standard deviation of the 18-hole scores for a golfer is more than 3.6 strokes. State Ho and Ha in words and in symbols. Then determine whether the hypothesis test for this claim is left-tailed, right-tailed, or two-tailed. Explain your reasoning State the null hypothesis in words and in symbols. Choose the correct answer below 0 A. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is equal to 3.6 strokes." The null hypothesis is expressed symbolically as "Ho: = 3.6." O B. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at most 3.6 strokes." The null hypothesis is expressed symbolically as "Ho: 3.6." ° C. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at least 3.6 strokes." The null hypothesis is expressed symbolically as "Ho: 236." The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is not 3.6 strokes." The null hypothesis is expressed symbolically as "Ho: 3.6." 0 D. State the alternative hypothesis in words and in symbols. Choose the correct answer below 0 A. The alternative hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is 3.6 strokes." The alternative hypothesis is O B. The alternative hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is more than 3.6 strokes." The alternative ° C. The alternative hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is less than 3.6 strokes." The alternative hypothesis expressed symbolically as, "Ha: = 3.6." hypothesis is expressed symbolically as, "Ha: > 3.6."Explanation / Answer
1)here for null hypothesis: option B is correct
2) for alternate hypothesis: option B is correct
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