A glob of putty thrown to the right bounces off a 0.600-kg cart initially at res

Question

A glob of putty thrown to the right bounces off a 0.600-kg cart initially at rest on a low-friction track. The collision takes 0.15 s, and the coefficient of restitution is 0.68. The cart has a final velocity of 1.0 m/s to the right, and the glob has a final velocity of 0.834 m/s to the left. Suppose that the positive x direction is to the right.

1.) What is the inertia of the glob?

2.) What is the x component of the average acceleration of the cart during the collision?

3.) What is the x component of the average acceleration of the glob during the collision?

Explanation / Answer

Here,

a)

let the mass of glob is m

initial velocity of glob is u1

Using conservation of momentum

m * u1 = 0.6 * 1 - m * 0.834 ---(2)

for coefficient of restitution

0.68 * u1 = 1 + 0.834

u1 = 2.7 m/s

putting in 1

m * 2.7 = 0.6 - m * 0.834

m = 0.170 Kg

the interia of glob is 0.170 Kg

b)

average acceleration of cart = (1 - 0)/.15

average acceleration of cart = 6.67 m/s^2

c)

average acceleration of the glob = (-0.68-2.7)/.15

average acceleration of the glob = 22.3 m/s^2

the average acceleration of the glob is 22.53 m/s^2

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