A basketball star covers 3.15 m horizontally in a jump to dunk the ball (see fig

Question

A basketball star covers 3.15 m horizontally in a jump to dunk the ball (see figure). His motion through space can be modeled as that of a particle at a point called his center of mass (which we shall define in Chapter 9). His center of mass is at elevation 1.02 m when he leaves the floor. It reaches a maximum height of 1.80 m above the floor and is at elevation 0.860 m when he touches down again. A: - Determine his time of flight (his "hang time").? B- Determine his horizontal velocity at takeoff? C- Determine his vertical velocity at takeoff.? D- Determine his takeoff angle.? E- For comparison, determine the hang time of a whitetail deer making a jump with center-of-mass elevations yi = 1.20 m, ymax = 2.55 m, and yf = 0.690 m?

Explanation / Answer

A: - Determine his time of flight (his "hang time").?

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