A basketball player can jump vertically 0.9 m.Assume that the jump interval (fro

Question

A basketball player can jump vertically 0.9 m.Assume that the jump interval (from lowering the body to his feet taking off) lasts for 0.3 s and the mass of the player is 90 kg. Ignore air resistance.

A)Determine the force that the the player exerts on the surface when he jumps.

Express your answer to one significant figure and include the appropriate units. Enter positive value if the force is upward and negative value if the force is downward.

B)Determine the force that the surface exerts on the player when he jumps.

Express your answer to one significant figure and include the appropriate units. Enter positive value if the force is upward and negative value if the force is downward.

C)Determine the force that the surface exerts on the player when he is landing back on the floor.

Express your answer to one significant figure and include the appropriate units. Enter positive value if the force is upward and negative value if the force is downward.

Explanation / Answer

Here ,

speed of player when he jumps is v ,

h = 0.90 m

v = sqrt(2 * g *h)

v = sqrt(2 * 9.8 * 0.9)

v = 4.2 m/s

A)

force extered by player on surface = mg + m * a

force extered by player on surface = -90 *(9.8 + (4.2)/.3)

force extered by player on surface = -2142 N

the force extered by player on surface is - 2142 N
B)

as force on player = - force extered by player on surface

force on player = -(-2142)

force on player = 2142 N

the force on player is 2142 N

C)

while landing back ,

force on player = force on player while going up

force on player = 2142 N

the force on player is 2142 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.