What are the strength and direction of the electric field at the position indica

Question

What are the strength and direction of the electric field at the position indicated by the dot in the figure(Figure 1)? A)Give your answer in component form. Assume that -axis is horisontal and points to the right, and -axis points upward (In N/C). B) What is the magnitude of the electric field at the position indicated by the dot in the figure (In N/C). C) What is the angle measured cw from the positive -axis of the electric field at the position indicated by the dot in the figure. (CW from +x-axis)

Explanation / Answer

What are the strength and direction of the electric field at the position indicated by the dot in the figure? http://session.masteringphysics.com/problemAsset/1071380/4/27.P30.jpg Give your answer in component form. Assume that x-axis is horisontal and points to the right, and y-axis points upward Give your answer as a magnitude and angle measured cw from the positive x-axis Express your answer using two significant figures in degress clockwise from the positive x-axis Here are the individual electric fields in vector notation: ||E(1)|| = kq/r^2 = (8.99e9 N*m^2/C^2)(10e-9 C)/(3.0e-2 m)^2 = 1.0e5 N/C E(1) = ||E(2)|| = (8.99e9 N*m^2/C^2)(5.0e-9 C)/(5.0e-2 m)^2 = 1.8e4 N/C E(2) = r = sqr(3^2 + 5^2) = 5.83 cm ||E(3)|| = (8.99e9 N*m^2/C^2)(10e-9 C)/(5.83e-2 m)^2 = 2.6e4 N/C ? = arctan(3/5) = 30.96° (measured counterclockwise from +x axis) E(3) = = Here is the total electric field: E = E(1) + E(2) + E(3) = ||E|| = sqr((-4.1e4)^2 + (8.6e4)^2) = 9.5e4 N/C ? = 180° + arctan(8.6e4/4.1e4) = 244.5° (measured clockwise from +x axis)

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