What are the solutions to this problem? Thanks! PROBLEM #2 (9 points): Given the
ID: 2962237 • Letter: W
Question
What are the solutions to this problem? Thanks!
Explanation / Answer
A) f(x)=x^4-x^2
x^4-x^x^2=0
x^2*(x^2-1) = 0
x^2*(x+1)*(x-1) =0
so the roots are 0,1,-1
B)for bisection method consider
f(2)>0 and f(0.5)<0
f(.5+2/2) = f(1.25) >0
we have f(1.25) and f(0.5)
f(0.5+1.25/2)=f(.875) <0
we have f(1.25) & f(.875)
f(1.25/.875) = f(1) = 0 so 1 is a root ...similarly by taking -2 and -0.5 we get -1 as root
bisection method cannot find the other root 0 as the function is not continuous at 0.
because if the function is not continuous we cannot consider the values to be assumed
C)The Newton
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