A 9.4-kg watermelon (30 degrees)and a 7.8-kg pumpkin (53 degrees) attached to ea

Question

A 9.4-kg watermelon (30 degrees)and a 7.8-kg pumpkin (53 degrees) attached to each other via a cord that wraps over a pulley, as shown. Friction is negligible everywhere in this system.

a) Find the accelerations of the pumpkin and the watermelon. Specify magnitude and direction.

b) If the system is released from rest, how far along the incline (cm)will the pumpkin travel in 0.30 s?

c) What is the speed (cm/s)of the watermelon after 0.20 s?

Explanation / Answer

7.8*g*sin(53)-T = 7.8 a T- 9.4*g*sin(30) = 9.4 a Adding both =>1.53 *g =17.2a =>a= 0.87m/sec^2 towards pumpkin b)s = 0+0.5*0.87*0.3^2 = 0.03915 m c)v=u+at =>v = 0.174m/sec

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