Two rigid rods are oriented parallel to each other and to the ground. The rods c

Question

Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The length of each rod is 0.90 m, while the mass of each is 0.090 kg. One rod is held in place above the ground, and the other floats beneath it at a distance of 8.2 multiplied by 10-3 m. Determine the current in the rods. i know i need to use mg=ILBSin(theata) and B=(uI)/2*phi*r and i need to solve for 2 variables, but im having trouble assigning my variables. i have m=.09 g=9.8 L=.9 r=8.2*10**-3? still looking for u?

Explanation / Answer

0.064(9.8)=0.6272N due to gravity, since both of them are floating, this indicates that there is a counter force holding it up so its 0.6272N is the force. use: eq 1: F=I L B sin x B=(4pie times 10^-7)/(2pie 8.2*10^-3m) substitute back in to eq 1. solve for I which is: 173.93A then its F=

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