Two resistors R 1 = 15.0 , and R 2 = 11.0 are connected with a 310 mH inductor,

Question

Two resistors R1 = 15.0 , and R2 = 11.0 are connected with a 310 mH inductor, a 12.0 V battery and a two-way switch as shown in the diagram below. At t = 0, the switch ab is closed.

If the switch ab is opened and ac is closed.

(d) Determine the time constant for this circuit after ac is closed. (Enter your answer to at least four decimal places.)
  (I've solved this one and the answer is 0.0119 s)

(e) What is the current in the inductor at t = 0.006 s after ac is closed?
A

(f) What is the voltage across the two resistors and the inductor at t = 0.006 s after ac is closed?

Explanation / Answer

current(I)=(V/R)(1-e(-Tt) ) where T-time constant

R- equivalent resistance= R1+R2= 26 ;

at t=0.006 ; I= 32.95 uA

f) voltage across R1 (V1) = I*R1= 494.29 uV

voltage across R2 (V2) = I*R2= 362.45 uV

Voltage sum=0 ; voltage across inductor= -856.74 uV

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