The figure below gives an overhead view of the path taken by a 0.165 kg cue ball

Question

The figure below gives an overhead view of the path taken by a 0.165 kg cue ball as it bounces from the rail of a pool table. The ball's initial speed is 1.90 m/s, and the angle ?1 = 30.0?. The bounce reverses the y component of the ball's velocity but does not alter the x component.

(a) What is?2?

(b) What is the change in the ball's linear momentum in unit-vector notation?

The figure below gives an overhead view of the path taken by a 0.165 kg cue ball as it bounces from the rail of a pool table. The ball's initial speed is 1.90 m/s, and the angle ?1 = 30.0?. The bounce reverses the y component of the ball's velocity but does not alter the x component. (a) What is?2? (b) What is the change in the ball's linear momentum in unit-vector notation?

Explanation / Answer

conservation of momentum along x
mv1sin1=mv2sin2

Along vertical velocity gets reversed

so v1=v2

1=2

change in momentum in vertical=mv2cos2-(-mv1cos1)=2mvcos1=0.543 kg.m/s

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