The figure at the right shows the same four resistors from last week\'s pre-lab

Question

The figure at the right shows the same four resistors from last week's pre-lab circuit shown above, but connected in a parallel circuit with the same battery as in that circuit. Take the current from the battery I_p as 400 mA. What is potential difference across each resistor? How do you know? What is the current through each of the resistors? How do you know? If we added a fifth resistor in a fifth branch how would that affect the potential difference across each of the resistors, the current through each of the resistors and the current I_p?

Explanation / Answer

Potential of the battery = 4 + 8 + 9 + 3 = 24 v

1)
In Parallel circut, Potential Difference across each resistor remains same, and will be equal to that of battery.
Potential Difference = 24 v

2)
Ip = 0.4 A
Req = 24/0.4 = 60
Current through each of the resistor =
Current through Ra, Ia = 24/Ra
Current through Rb, Ia = 24/Rb
Current through Rc, Ic = 24/Rc
Current through Rd, Id = 24/Rd

values of Resisotrs are not mentiond, please take it from previous investigation and substitue value to get answer.

3)
Effects on adding Fifth Resistor in parallel,
No Effect on Potential Difference.
Current through Each of the Resistor's would remain same as it was before.
Current Ip would Increase.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.