A 5.0 kg block slides along a frictionless horizontal surface with a speed of 9.

Question

A 5.0 kg block slides along a frictionless horizontal surface with a speed of 9.0 m/s. After sliding a distance of 7.0 m, the block makes a smooth transition to a frictionless ramp inclined at an angle of 30 degrees to the horizontal. The acceleration of gravity is g = 9.8 m/s2. Consider the zero of the vertical y coordinate and the zero of the potential energy at the level of the horizontal surface. A) Which is the kinetic energy of the block as it moves along the horizontal surface B) What distance along the ramp does the block slide before coming momentarily to a stop? C) What is the potential energy of the block when it comes momentarily to a stop D) What is the total mechanical energy of the block when it comes momentarily to a stop? E) Which is the maximum height it reaches?

Explanation / Answer

d. W = Fd W = K K = 1/2mv^2 K = 202.5 J this will all be converted to potential energy up at the top of the ramp and will go up a height mgh = 202.5 (not like you need to know height but anyways) so potential energy will be 202.5 J e. mechanical energy is U + K it will all be U, because it is stopped but it wil still be 202.5 J

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