PART A: Find the fundamental frequency and the frequency of the first three over

Question

PART A:
Find the fundamental frequency and the frequency of the first three overtones of a pipe 95.0 cm long, if the pipe is open at both ends.

Please enter your answer as four numbers, separated with commas.

PART B:
Find the fundamental frequency and the frequency of the first three overtones of a pipe 95.0 cm long, if the pipe is closed at one end.

Please enter your answer as four numbers, separated with commas.

PART C:
If the pipe is open at both ends, what is the number of the highest harmonic that may be heard by a person who can hear frequencies from 20.0 Hz to 2.00

Explanation / Answer

for a pipe open at both ends; f = nv/2L fo = v/2L = 173.68Hz f1 = v/L = 347.37Hz f2 = 3v/2L = 521.05Hz f3 = 2v/L = 694.74Hz for a pipe closed at one end; f = nv/4L where n= 1,3,5...... f0 = v/4L = 86.84Hz f1= 3v/4L = 260.53Hz f2 = 5v/4L = 434.2Hz f3 = 7v/4L = 607.88Hz 20000 = nv/2L n = 115.15 So, he can hear maximum upto 115th harmonic..... 20000 = nv/4L n = 230.3 but only odd harmonics are possible So, he can hear upto 229th harmonic.....

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