PART A How many milliliters of a 5.90 M NaOH solution are needed to provide 0.36

ID: 1027712 • Letter: P

Question

PART A

How many milliliters of a 5.90 M NaOH solution are needed to provide 0.360 mol of NaOH?

PART B

Calculate the molarity of a solution prepared by dissolving 12.1 g of Na2CrO4 in enough water to produce a solution with a volume of 880. mL .

Express the molarity to three significant digits.

PART C

How many moles of KBr are present in 100. mL of a 0.108 M solution?

Express the amount in moles to three significant digits.

PART D

How many milliliters of 6.3 M HCl solution are needed to obtain 0.10 mol of HCl?

Express the volume in milliliters to two significant digits.

Part A

Volume =mole/molarity

Volume =0.360/5.90=0.610 L

1L=1000ml then 610 ml answer

Part B molar mass of na2cro4=161.97g/mol

Mole =1.21/161.97=0.0075 mole

Molarity=0.0075/0.880 L=0.009 M

Part C

Mole=0.108*0.1L=0.011 mole

Part D volume =0.10/6.3=15.87 ml

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