Two motocross bikes start from one corner of a square field and go to the corner

Question

Two motocross bikes start from one corner of a square field and go to the corner diagonally opposite in the same time T. They both start from the same place and take different routes. One travels along the diagonal with constant acceleration A and the other accelerates momentarily and the traveles along the edge of the field with constant speed of V. What is the relationship between A and V? Assume a negligible acceleration for the bike rider traveling along the edge. Please show you work and the set up. I don't have a clue what they want. Thank you

Explanation / Answer

You haven't done anything wrong. You've just missed the fact that: sqt(2) / 2 = 1/ sqt(2) The two expressions are equivalent!!! :

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