a) A uniform steel beam of length 5.8 m has a mass of 420 kg. One end of the bea
ID: 2189772 • Letter: A
Question
a) A uniform steel beam of length 5.8 m has a mass of 420 kg. One end of the beam is bolted to a vertical wall. The beam is held in a horizontal position by a cable attached between the other end of the beam and a point on the wall. The cable makes an angle of 25 degrees above the horizontal. A load whose mass is 280 kg is hung from the beam at a point that is 3.4 m from the wall. Find the magnitude of the tension in the supporting cable.
b) Find the magnitude of the force R exerted on the end of the beam by the bolt that attaches it to the wall.
Explanation / Answer
Take summation of moments about the bolt. (5.8)(T)(sin 25) - W1(2.9) - W2(3.4) = 0 where T = tension in the supporting cable W1 = weight of the uniform steel beam = 420*9.8 N W2 = weight of the load on the beam Substituting values, (5.8)(T)(0.4226) - 420*9.8(2.9) -280*9.8(3.4) = 0 T = 8675.8 Newtons **************************************
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