a) A pellet with a mass of 0.5kg moves at a velocity of 10m/s and it collides wi

Question

a) A pellet with a mass of 0.5kg moves at a velocity of 10m/s and it collides with another pellet rested with mass of 0.75kg. After collision, both pellets move together along a hill. What is the speed of both pellets right after the collision? What conservation law should we use to find VF?

b) Determine the total kinetic energy of both pellets before and after the collision. Will the kinetic energy conserved? Why?

c) Both pellets will reach to a maximum height at point H. Determine the maximum height, hmax. What conservation law should we use to find hmax?

Explanation / Answer

A) momentum conservation

0.5*10+0=(0.75+0.5)*v

V= 4m/s

B) initial kinetic energy=(1/2)*0.5*10^2+0=25J

After collision=(1/2)*(0.75+0.5)*4^2=10J

Not conserved .

C) engery conservation

10J =(0.75+.5)*9.8*H

H=81.6 cm

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