a) A double-slit experiment is set up using red light ( = 748 nm). A first order

Question

a) A double-slit experiment is set up using red light ( = 748 nm). A first order bright fringe is seen at a given location on a screen. What wavelength of visible light (between 380 nm and 750 nm) would produce a dark fringe at the identical location on the screen? __nm

b) A new experiment is created with the screen at a distance of 2 m from the slits (with spacing 0.11 mm). What is the distance between the second order bright fringe of light with = 686 nm and the third order bright fringe of light with = 401 nm? (Give the absolute value of the smallest possible distance between these two fringes: the distance between bright fringes on the same side of the central bright fringe.)

|x| =__m

Explanation / Answer

a)

from the given problem it is clear that

delta X / d = constant

wavelength x1 / d = wavelength3 /2 / d

748 = 1.5 x wavelength

wavelength = 498.666 nm

b)

X = (2x686 - 3x401 )x10^-9x2/0.11x10^-3

X = 0.00307 m

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