a) A driver has a reaction timeof 0.50s, and the maximum deceleration of her car
ID: 1760698 • Letter: A
Question
a) A driver has a reaction timeof 0.50s, and the maximum deceleration of her car is 6.0m/s2. She is driving at 20 m/s when suddenly she sees anobstacle in the road 50m in front of her. Can she stop the car intime to avoid a collision? b) In assessing your solutionto this problem, please comment on what this problem tells youabout safe driving habits. Please provide your input guys, it'd bereally appreciate to see the step-by-step method for part a andyour reasoning for part b of the question. Thanksagain! a) A driver has a reaction timeof 0.50s, and the maximum deceleration of her car is 6.0m/s2. She is driving at 20 m/s when suddenly she sees anobstacle in the road 50m in front of her. Can she stop the car intime to avoid a collision? b) In assessing your solutionto this problem, please comment on what this problem tells youabout safe driving habits. Please provide your input guys, it'd bereally appreciate to see the step-by-step method for part a andyour reasoning for part b of the question. Thanksagain! a) A driver has a reaction timeof 0.50s, and the maximum deceleration of her car is 6.0m/s2. She is driving at 20 m/s when suddenly she sees anobstacle in the road 50m in front of her. Can she stop the car intime to avoid a collision? b) In assessing your solutionto this problem, please comment on what this problem tells youabout safe driving habits. Please provide your input guys, it'd bereally appreciate to see the step-by-step method for part a andyour reasoning for part b of the question. Thanksagain!Explanation / Answer
a) after the reaction of 0.50s, the distance to stop is: 50m - 0.50*20m/s = 40m let the distance to stop is d vf2 - vi2 =2ad d = (vf2-vi2)/2a =(0-(20m/s)2)/(2*6.0m/s2) = 33.33m she only need 33.33m to stop but get 40m, so she can stop thecar in time to avoid a collision b) when you observed any situation, stop as soon as possible. ifshe spend another 0.5s to react she will only get 50m-1.0s*20 = 30m to stop, that will notenough to avoid collision. it is better to stop imeediately when you need.Related Questions
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