a) A person has her near-point (NP) at a distance of 1.5 m. What optical power (
ID: 1493495 • Letter: A
Question
a) A person has her near-point (NP) at a distance of 1.5 m. What optical power (in Diopters) does she need to have her vision corrected?
b) A slit formed by an incompletely shut closet door lets light into the closet. This results in a diffraction pattern on the back wall of the closet. How wide is the central maximum (use the distance between the first minimum on one side of the maximum to the first minimum on the other side)? The light's wavelength is 500 nm, the slit is 1 mm wide, and the distance from the slit to the back wall is 1 m
Explanation / Answer
object distance p = 25 cm
image distance q = -1.5 m = -150 cm
from lens equation
1/p + 1/q = 1/f
1/25 - 1/150 = 1/f
f = 30
power P = 1/f(in meters)
P = 1/0.3
P = 3.33 D
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b)
y = m*lambda*R/d
y = 1*500*10^-9*1/10^-3
y = 0.0005 m
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