The horizontal beam in the figure below (Figure 1) weighs 180N , and its center

Question

The horizontal beam in the figure below (Figure 1) weighs 180N , and its center of gravity is at its center.

Part B Find the horizontal component of the force exerted on the beam at the wall.

Part C Find the vertical component of the force exerted on the beam at the wall.

Explanation / Answer

the acute angle at the point of suspension = tan inverse 3/4 = 36.87 deg the tension in the string = T at the point of suspension : t sin 36.87 = 300 => T = 500 N horizontal component of this tension is balanced by the reaction from the wall on the beam B) horizontal reaction = 500 cos 36.87 = 400 N C) now the net force in vertical direction on the system should be 0 the vertical and horizontal components of the tension in the string shall get cancelled by the weight and the horizontal reaction from the wall respectively so the vertical reaction = weight of the beam = 180 N

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