probability 9. (3 points) We often use the product rule to predict the number of
ID: 218623 • Letter: P
Question
probability 9. (3 points) We often use the product rule to predict the number of progeny in agricultural crosses combining desired traits from two diverged parents Think of tomato plants, for instance, which have five desirable fruit characteristics: sweetness, size, color, texture, and resistance to bruising Consider a cross between two parental lines, each of which have four of these desirable traits: Aa Bb cc Dd EE X Aa Bb CC dd Ee. Assume the five genes assort independently a. How many different phenotypes will be present in the next b. What proportion of the progeny from this cross will look like the first c. What proportion of the progeny will have all five traits: AJ- B/- C/- D/ generation? parent? E/-?Explanation / Answer
a- In case of the cross between Aa and Aa we will get two phenotypes.
In case of the cross between Bb and Bb we will get two phenotypes.
In case of the cross between cc and CC we will get one phenotype.
In case of the cross between Dd and dd we will get two phenotypes.
In case of the cross between EE and Ee we will get one phenotype.
So total phenotype will be 2*2*1*1*2 = 8 phenotypes.
B- Cross between CC and cc will give us the progeny which will have Cc genotype, which is not present in any of the parent. SO answer is zero.
C-
In case cross between Aa and Aa, the proportion of A_ will be 3/4
In case cross between Bb and Bb, the proportion of B_ will be 3/4
In case cross between cc and CC, the proportion of C_ will be 1
In case cross between Dd and dd, the proportion of D_ will be 1/2
In case cross between EE and Ee, the proportion of E_ will be 1
So the proportion of progeny which have A_B_C_D_E_ will be 3/4*3/4*1*1/2*1
9/32.
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