A 12.0 g rifle bullet is fired with a speed of 740 m/s into a ballistic pendulum

Question

A 12.0 g rifle bullet is fired with a speed of 740 m/s into a ballistic pendulum with a mass of 8.00 kg, suspended from a light and long cord. Ignore air resistance. Compute the initial kinetic energy of the bullet Compute the kinetic energy of the bullet and block after the bullet got stuck in the block Compute the max height through which the block would rise

Explanation / Answer

(a) the energy is: E=mv^2/2=3285.6 J (b) use conservation of momentum to find a speed of a pendulum: m1v=(m1+m2)u --> u=m1v/(m1+m2)=1.1 m/sec --> energy of the pendulum E=m2*u^2/2=4.91 J (c) use conservation of energy: initial block kinetic energy is transfered to the potential energy mgh=4.91 --> h=0.062m

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