A particle has a charge of q = +5.8 ?C and is located at the origin. As the draw

Question

A particle has a charge of q = +5.8 ?C and is located at the origin. As the drawing shows, an electric field of Ex = +246 N/C exists along the +x axis. A magnetic field also exists, and its x and y components are Bx = +1.1 T and By = +1.7 T. Calculate the force (magnitude and direction) exerted on the particle by each of the three fields when it is (a) stationary, (b) moving along the +x axis at a speed of 345 m/s, and (c) moving along the +z axis at a speed of 345 m/s.

Explanation / Answer

if the elctrical field is E and magnetic field is B,charge of the particle is q and velocity is v. then force on the charged particle=q*(E+cross product of v and B) a.) stationary ==>v=0 so F=q*E=1.4268 *10^(-3) N,long the +ve x-axis b.) v=345 i F=q*E+q*(cross product of 345 i and (1.1 i +1.7 j))=1.4268*10^(-3) i+3.4*10^(-3) k c,) v=345 k F=q*E+q*(cross product of 345 k and (1.1 i +1.7 j))=1.4268*10^(-3) i-3.4*10^(-3) i+2.2*10^(-3) j=-1.9732*10^(-3) i +2.2*10^(-3) j

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.