A 49.7 kg sled starts at rest on a horizontal road. The coefficient of kinetic f

Question

A 49.7 kg sled starts at rest on a horizontal road. The coefficient of kinetic friction between the sled and the road is ?k = 0.247. A man pulls the sled a distance 5.08 m along the ground by exerting a constant force of magnitude 430 N on a rope that makes a 28.4o angle above the horizontal. Find:

a) the magnitude of the normal force exerted by the ground on the sled
N

b) the total work done by the man
J

c) the work done by the frictional force on the sled
J

d) the speed of the sled after it has moved 5.08 m
m/s

e) the rate at which the man is doing work after the sled has moved 5.08 m
W

Explanation / Answer

a)N=mg-F sin 28.4=282.54 b)W=F cos 28.4 * 5.08=1921.5 c)Wf=u*N * 5.08=354.52 d).5*m*v^2=W-Wf so v=7.94 d)rate=F cos 28.4 * v/2=1501.64

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