A 49.9-? resistor is connected in parallel with a 175.7-? resistor. This paralle
ID: 1263190 • Letter: A
Question
A 49.9-? resistor is connected in parallel with a 175.7-? resistor. This parallel group is connected in series with a 27.4-? resistor. The total combination is connected across a 11.9-V battery. Find (a) the current and (b) the power dissipated in the 175.7-? resistor
A 49.9-? resistor is connected in parallel with a 175.7-? resistor. This parallel group is connected in series with a 27.4-? resistor. The total combination is connected across a 11.9-V battery. Find (a) the current and (b) the power dissipated in the 175.7-? resistorExplanation / Answer
49.9 in parallel with 175.7 is 38.865 ohms
in series with 27.4 that is 66.265 ohms
total current is
I = E/R = 11.9/66.265 = 0.17958amps
voltage across parallel pair is
E = IR = 0.17958 x 38.865 = 6.979 volts
that causes current in the 175.7 ohm resistor
I = E/R = 6.979 /175.7 = 0.03972 amp
Power is EI = 0.03972x 6.979 = 0.27723 watts
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