A charged capacitor is discharged through a resistor. The current I(t) through t

Question

A charged capacitor is discharged through a resistor. The current I(t) through this resistor, determined by measuring the voltage VR(t) = I(t)R with an oscilloscope, is shown in the graph. The total energy dissipated in the resistor is 2.20 10-4 J.

(a) Find the capacitance C, the resistance R, and the initial charge Q0 on the capacitor. [Hint: You will need to solve three equations simultaneously for the three unknowns. You can find both the initial current and the time constant from the graph.]
C = F
R = ?
Q0 = C

(b) At what time is the stored energy in the capacitor 5.80 10-5 J?
s

Explanation / Answer

58.5 µF 12.3mJ 0.707V0 4.16ms

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