A wooden block with mass 1. 00kg js placed against a compressed spring at the bo

Question

A wooden block with mass 1. 00kg js placed against a compressed spring at the bottom of a slope inclined at an angle of 26. 0 degree (point A). When the spring is released, it projects the block up the incline. At point B a distance of 5. 95m up the incline from A the block is moving up the Incline at a speed of 5. 25 m/s and is no longer in contact with the spring. The coefficient of kinetic friction between the block and incline is muk = 0. 45. The mass of the spring is negligible. Calculate the amount of potential energy that was initially stored in the spring. Take free fall acceleration to be 9. 80m/s2.

Explanation / Answer

potential energy of spring =1/2*k*x*x
energy lost in friction= mgcos * d= 0.45*1*9.8*cos26*5.95 = 23.8 joules

kinetic energy = 1/2*m*v*v=1/2*1*5.25*5.25=13.78 joules

23.8+13.78 = 1/2*k*x*x =PE of spring

PE of spring = 37.58 Joules

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