A women;s femurs (upper- leg bones) are 29 cm long, with average diameter 3.8 cm

Question

A women;s femurs (upper- leg bones) are 29 cm long, with average diameter 3.8 cm. Her upper-body mass (i.e., the mass supported by her two legs) is 48kg. Assuming the femur has a Young's modulus of 5.0 x 10^9 N/m^2 under compression, by how much is each femur compressed when the woman is standing?

The answer is 1.2 10^-5 m (provided by my proffesso,r to let us know if we solved it correctly)

I need help on how to solve this problem.. If you can show step by step and formulas used. That would be great!

Explanation / Answer

Apply Y = FL/A(delta L)

5.0 X 10^9 = (24)(9.8)(.29)/(pi)(.019)^2(delta L)

delta L = 1.20 X 10^-5 m

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