A proton traveling at 4.40km/s suddenly enters a uniform magnetic field of 0.740
ID: 2173287 • Letter: A
Question
A proton traveling at 4.40km/s suddenly enters a uniform magnetic field of 0.740 T , traveling at an angle of 55.0 with the field lines (see the figure (Figure 1) ).
a)Find the direction of the force this magnetic field exerts on the proton.
Answer choices are : the force directed into the page, the force is directed out of page
b)Find the magnitude of the force this magnetic field exerts on the proton.
c)If you can vary the direction of the proton's velocity, find the magnitude of the maximum and minimum forces you could achieve.Answer the question in the order indicated. Separate your answers using comma.
d)How the velocity should be oriented to achieve the forces in part (C).
Answer choices are : a)
answer choices are :the force directed into the page, the force is directed out of page.
F)What would the answers to part (B) be if the proton were replaced by an electron traveling in the same way as the proton?
is maximum whenis perpendicular to.is minimum whenis perpendicular to. is maximum whenis perpendicular to.is minimum whenis either parallel or antiparallel to. is maximum whenis parallel to.is minimum whenis perpendicular to.Explanation / Answer
F=q(vXb)=qvb sin 55=.82*qvb dir : into the paper that is opposite from the reader to the paper or inwards in xy plane.. b)F max= is at 90 degree Fm=qvb
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