A proton moves with a speed of 1.0×107m/s in the directions shown in the figure.

Question

A proton moves with a speed of 1.0×107m/s in the directions shown in the figure. A 0.50 T magnetic field points in the positive x-direction.(Figure 1)

Part A

What is the magnitude of the magnetic force F  on the proton in figure (a)?

Express your answer using two significant figures.

Part B

What is the direction of the magnetic force F  on the proton in figure (a)?

A) +x direction

B) +y direction

C) +yz direction

D) - xy direction

E) magnetic force is 0

Part C

What is the magnitude of the magnetic force F  on the proton in figure (b)?

Express your answer using two significant figures.

Part D

What is the direction of the magnetic force F  on the proton in figure (b)?

A) +x direction

B) +y direction

C) +yz direction

D) -xy direction

E) magnetic force is 0

Explanation / Answer

a) foece=qvB sintheta

f=1.6*10^-19*10^7*0.5*sin45

f=0.566*10^-12 N

b) along y direction( perpendicular to the plane)

c) theta =180

force=0

d) magnetic force =0

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