Two forces, 376 N at 8 degrees and 314 N at 26 degrees are applied to a car in a

Question

Two forces, 376 N at 8 degrees and 314 N at 26 degrees are applied to a car in an effort to accelerate it. What is the magnitude of the resultant of these two forces? answer in units of N

Find the direction of the resultant force (in relation to forward, with counterclockwise considered positive) Answer in degrees from the positive x-axis with counter-clockwise positive, with the limits of -180 degrees to 180 degrees. Answer in units of degrees.

If the car has a mass of 3169 kg, what magnitude of acceleration does it have? Ignore friction!! Answer in units of m/s^2

Explanation / Answer

Fx = 376*cos8 + 314*cos26 = 654.56 N Fy = 376*sin8 + 314*sin26 = 190.2 N resultant force magnitude = 681.6 N acceleration = 681.6 /3169 = 0.215 m/s^2

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