if duchenne muscular dystrophy (DMD) a x linked recessive condition in humans ha

Question

if duchenne muscular dystrophy (DMD) a x linked recessive condition in humans has a frequency of 1/10000 females in hypothetical population.
A) what is the frequency of males with DMD in this population?
B) assuming the population is in hardy weinberg equilibrium, what percentage of females in the population are carriers/heterozygous? if duchenne muscular dystrophy (DMD) a x linked recessive condition in humans has a frequency of 1/10000 females in hypothetical population.
A) what is the frequency of males with DMD in this population?
B) assuming the population is in hardy weinberg equilibrium, what percentage of females in the population are carriers/heterozygous?
A) what is the frequency of males with DMD in this population?
B) assuming the population is in hardy weinberg equilibrium, what percentage of females in the population are carriers/heterozygous?

Explanation / Answer

A. Female q2 f(Xd Xd) is 1/10000 q2 = 0.0001
q = 0.01

Male has only one X linked recessive gene. So,
f(Xd Y) = q = 0.01

2. Female
P+q = 1
p+0.01=1
p = 0.99
f(XD Xd) = 2Pq
         = 2 X 0.99 X 0.01
         = 0.0198

         =1.98 %

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