if a person breathes 10 liters per minute of air at 68 degrees F and 50% relativ
ID: 2273454 • Letter: I
Question
if a person breathes 10 liters per minute of air at 68 degrees F and 50% relative humidity , how much water per day must the internal membranes supply to saturate the air at 98.6 degrees F? (assume all moisture is exhaled) if each gram of water extracts 580 calories as it is vaporized , how much daily heat loss in kilocalories (food calories) does this represent ? (saturation vapor pressure at 20 degrees C is 17.3 g/m cubed and at 37 degrees C is 44.0 g/m cubed (grams per cubic meter).
water per day :_____________ans
_______g/day
________liters/day
energy per day lost:_____________ans (food calories)
Explanation / Answer
l0 liters / min = 600 l / hr = 14,400 l /day
68 F = 20 C & 98.6 F = 37 C
580 cal / g @ 20 C = 25520 cal/m or 25.520 kcal / m
580 cal / g @ 37 C = 10034 cal / m or 10.034 kcal / m
*water has about 1000 grams in a liter*
Inhale 50% of 17.3 = 8.65 g/m
Exhale 100% of 44 g/m
Relative Humidity = content of moisture / capacity
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