A charge +q is located at the origin. A charge -2q is at 3.65 m on the x axis. (

Question

A charge +q is located at the origin. A charge -2q is at 3.65 m on the x axis.
(a) For what finite value of x is the electric field zero?
5 . m
To the right of both charges, which charge is always closest? Does it have the smaller or larger charge? At what locations are there two field contributions that can cancel to produce zero net field? The response you submitted has the wrong sign.
(b) For what finite value(s) of x is the electric potential zero? smaller value 6 . m
Write an expression for the potential as a function of x to the left of both charges, between the two charges, and to the right of both charges. Solve for the value(s) of x for which the potential is zero. The response you submitted has the wrong sign.
larger value 7 . m

Explanation / Answer

Let q1 = -10.0 nC , and q2 = 20.0 nC E1(P) + E2(P) = 0 |E1| = |E2| |q1|/r1^2 = q2/r2^2 r2/r1 = sqr(q2/|q1|) = sqr 2 r2 = r1 + d Solving : r1 = d/(sqr2 -1) = 33.8 cm ; r2 = 47.8 cm (a) V = (1/4pi €o)(q2/r2 + q1/r1) = 110 V (b) V=0 |q1|/r1 = q2/r2 r2 = 2 r1 ; r2 + r1 = d solving r2 = 28/3 cm ; r1 = 14/3 cm E = E1 + E2 = (1/4pi€o)(|q1|/r1^2 + q2/r2^2) E is // at X axis and direct from q2 to q1.

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