A 3.00 kg block on a horizontal floor is attached to a horizontal spring that is

Question

A 3.00 kg block on a horizontal floor is attached to a horizontal spring that is initially compressed 0.0340 m . The spring has force constant 895 N/m. The coefficient of kinetic friction between the floor and the block is 0.42 . The block and spring are released from rest and the block slides along the floor.

Part A
What is the speed of the block when it has moved a distance of 0.0150 from its initial position? (At this point the spring is compressed 0.0190 .)
Express your answer with the appropriate units.

Explanation / Answer

Initial potential energy of sprinf block system=final potential energy+kinetic energy of block+energy loss to friction

0.5*895*0.0342=0.5*895*0.0192+0.5*3*v2+0.42*3*9.8*0.015

Solving for v,

v=0.337m/s=33.7cm/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.