A 3.0 m length of wire is made by welding the end of a 100 cm long silver wire t

Question

A 3.0 m length of wire is made by welding the end of a 100 cm long silver wire to the end of a 200 cm long copper wire . Each piece of wire is 0.60 mm in diameter. The wire is at room temperature, so the resistivities are as given in the table below. A potential difference of 6.0 V is maintained between the ends of the 3.0 m composite wire.

A 3.0 m length of wire is made by welding the end of a 100 cm long silver wire to the end of a 200 cm long copper wire . Each piece of wire is 0.60 mm in diameter. The wire is at room temperature, so the resistivities are as given in the table below. A potential difference of 6.0 V is maintained between the ends of the 3.0 m composite wire. Vector E in the silver? V/m (e) What is the potential difference between the ends of the sliver section of wire? V vector E in the copper? V/m (d) What is the magnitude of (a) What is the current in the copper section? A (b) What is the current in the silver section? A (c) What is the magnitude of

Explanation / Answer

apply resistance R = rho L/A

R of Copper = 1.67 e-8 * 0.2/(3.14 * 0.3e-3 * 0.3e-3)

Rc = 0.0118 ohms

use ohms law as V= IR

so current I across Copper = V/R

i = 6/0.0118

i = 507.66 Amps

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again Resistance of Silver

Rs = 1.47 e-8 *0.1/(3.14 * 0.3e-3*0.3e-3)

Rs = 0.0052 ohms

so

current Is = 6/0.0052   = 1153.47 Amps

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C. apply E = V/L

Ec = 6/0.2

Ec = 30 V/m
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E s = 6/0.1 = 60 V/m

e. V = 6 V

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