A luggage handler pulls a suitcase of mass 29.7 kg up a ramp inclined at an angl

Question

A luggage handler pulls a suitcase of mass 29.7 kg up a ramp inclined at an angle 30.8 degrees above the horizontal by a force, F, of magnitude 104 N that acts parallel to the ramp. The coefficient of kinetic friction between the ramp and the incline is 0.267. The suitcase travels a distance 3.75 m along the ramp.

A) Calculate the work done on the suitcase by the force,F.
B) Calculate the work done on the suitcase by the gravitational force.
C) Calculate the work done on the suitcase by the normal force.
D) Calculate the work done on the suitcase by the friction force.
E) Calculate the total work done on the suitcase.
F) If the speed of the suitcase is zero at the bottom of the ramp, what is its speed after it has traveled 3.75 m along the ramp?

Explanation / Answer

a) Fxd= 104x3.75 = 390 J b) mg x 3.75 sin 30.8 = 149 J c)Zero as perpendicular to direction of displacement d) Mgcos theta = normal friction = uN = 66.75 N Work = frictionx d =250.3 J e)390-149-250.3=-9.3 total work done = 9.3 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.