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A loudspeaker of mass 23.0 kg is suspended a distance of h = 1.40 m below the ce

ID: 2037298 • Letter: A

Question

A loudspeaker of mass 23.0 kg is suspended a distance of h = 1.40 m below the ceiling by two cables that make equal angles with the ceiling. Each cable has a length of l = 3.10 m .

Part A

What is the tension T in each of the cables?

Use 9.80 m/s2 for the magnitude of the acceleration due to gravity.

A loudspeaker of mass 23.0 kg is suspended a distance of h = 1.40 m below the ceiling by two cables that make equal angles with the ceiling. Each cable has a length of l = 3.10 m .

Part A

What is the tension T in each of the cables?

Use 9.80 m/s2 for the magnitude of the acceleration due to gravity.

T =   N  

Explanation / Answer

Let the angle made with vertical is ?

=>cos? = 1.40/3.10 = 0.451

Thus By mg = 2Tcos?

=>T = (23 x 9.8)/(2 x 0.451)

=>T = 249.889 Newton

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