A loudspeaker of mass 16.0 kg is suspended a distance of h = 2.40 m below the ce

Question

A loudspeaker of mass 16.0 kg is suspended a distance of h = 2.40 m below the ceiling by two cables that make equal angles with the ceiling. Each cable has a length of l = 3.90 m . (Figure 1)

Part A

What is the tension T in each of the cables?

Use 9.80 m/s2 for the magnitude of the acceleration due to gravity.

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A loudspeaker of mass 16.0 kg is suspended a distance of h = 2.40 m below the ceiling by two cables that make equal angles with the ceiling. Each cable has a length of l = 3.90 m . (Figure 1)

Part A

What is the tension T in each of the cables?

Use 9.80 m/s2 for the magnitude of the acceleration due to gravity.

1 of 1

Explanation / Answer

sin(theta) = h / L

theta = sin^-1(2.40 / 3.90 )

theta = 38 deg

in vertical, Fnet = 2 T sin(theta) - m g = 0

2 T sin38 = (16 x 9.8 )

T = 127.4 N

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